Mathematics, 09.01.2022 14:20 slimt3763

Given: A(2,1), B(0,5), C(-1,2), AB and BC, mpab = 1/2, mpbc = -1/3, midpoint of AB = (1,3), midpoint pf BC = (-1/2, 7/2). Find standard form equation of line perpendicular to AB through the midpoint .
Use the formula m = y-y1/ x-x1

A. x + 3y = -10
B. x - 2y = -5
C. -x - 2y = 6

Answers: 3

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Given: A(2,1), B(0,5), C(-1,2), AB and BC, mpab = 1/2, mpbc = -1/3, midpoint of AB = (1,3), midpoint...

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Given: A(2,1), B(0,5), C(-1,2), AB and BC, mpab = 1/2, mpbc = -1/3, midpoint of AB = (1,3), midpoint pf BC = (-1/2, 7/2). Find standard form equation of line perpendicular to AB through the midpoint . Use the formula m = y-y1/ x-x1 A. x + 3y = -10 B. x - 2y = -5 C. -x - 2y = 6

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Another question on Mathematics

Given: A(2,1), B(0,5), C(-1,2), AB and BC, mpab = 1/2, mpbc = -1/3, midpoint of AB = (1,3), midpoint pf BC = (-1/2, 7/2). Find standard form equation of line perpendicular to AB through the midpoint .
Use the formula m = y-y1/ x-x1

A. x + 3y = -10
B. x - 2y = -5
C. -x - 2y = 6