What is the slope for the graph below?

-3/2 I may not be completely right

first u can notice that the graph is going down right?

then it must be -

so it cant be 2/3 or 3/2

then u are looking for a dot that is Integrates with the horizontal and vertical axis like( 0,-1)

u are going one to the right then going down till u touches the ax again if u notice u will go down -1.5 so the slope is -1.5

-3/2 is -1.5

so the slope is -1.5( -3/2)

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

jml angle lkj & angle mj = lm