The price of a train ticket consists of an initial fee of $
5
$5dollar sign, 5 plus a fee of
$
2.75
$2.75dollar sign, 2, point, 75 per stop. Julia has
$
21
$21dollar sign, 21 and would like to travel
50
5050 kilometers. She wants to know the largest number of stops she can afford to buy on a ticket

Step-by-step explanation:

this is very difficult to read.

if I understand correctly, then a train ticket costs first an initial fee of $5, and then $2.75 per stop.

Julia has $21.

to find the max. number of stops she can buy, we need first to deduct the $5 initial fee. she would need to pay that no matter how many stops she wants to have.

so, she has 21-5 = $16 available for stops.

as 1 so costs $2.75, we need to find out how often 2.75 fits into 16.

that is what division is for.

by calculating 16/2.75 we find out exactly how often 2.75 fits into 16.

now, with a calculator this is easy.

but let's say, we need to do this by hand.

then we should consider 2.75 as a fraction.

it is, in fact, 2 3/4 or 8/4 + 3/4 = 11/4.

remember, dividing by a fraction is the same as multiplying by the upside-down fraction.

so, 16/ 11/4 = 16 × 4/11.

to understand it even better we can write 16 as fraction too : 16/1.

that means we have

16/1 × 4/11 = (16×4) / (11×1) = 64/11 = 5 9/11 = 5.818181...

so, she can buy max. 5 stops. for the 6th stop she does not have the full money anymore.

no solution

step-by-step explanation:

there is not enough information in the problem to solve.