Three tankers contain 403 liters, 434 liters and 465 liters of diesel respectively. find the maximum capacity of a container that can measure the diesel of the three containers exact number of times

Given capacities of containers

We need HCF of 403,434,465

HCF is 31L

Maximum capacity 31L

Step-by-step explanation:

Three tankers contain 403 liters, 434 liters and 465 liters of diesel respectively. find the maximum capacity of a container that can measure the diesel of the three containers exact number of times

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

the answer is c)8

step-by-step explanaction: