Solve the following inequality using both the graphical and algebraic approach: 5 minus x less-than 2 (x minus 3) + 5 Graph A On a coordinate plane, a line goes through (0, 5) and (5, 0). Another line goes through (negative 2, negative 4) and (2, 3). The lines intersect at (2, 3). Graph B On a coordinate plane, a line goes through (0, 0) and (2, negative 6). Another line goes through (0, negative 8) and (2, negative 6). a. x less-than 2 Graph A b. x greater-than 2 Graph A c. x less-than 2 Graph B d. x greater-than 2 Graph B

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step-by-step explanation:

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4

i think the answer is b x = 1, y = 35/2