The perimeter of a rectangle is 54 cm and its width is 11 cm longer than its length. What is the width? Show your work using an equation. Write just the width below.

19cm

Step-by-step explanation:

Perimeter =54 cm

let the length be x

the width is 11cm longer than the length so it will be x + 11

and we have 2 lengths and 2 widths in a rectangle, so the equation is:

x+x+x+11cm+x+11cm=54cm

4x+22cm=54cm

4x=54cm-22cm

4x=32cm

divide both sides by 4 to find x

x=8cm

previously I said the length is x and the width is x+11, and we've found the length which is x, so to find the width:

x+11cm

8cm+11cm=19cm

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x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15