The function g is defined by g (x)=(x-3)^2. if g(a)= a^2 what is the value of a?

Step-by-step explanation:

g(x)=4(x−3)2+1  

g(x)=4×(x−3)2+1

g(x)=4×(x2−6x+9)+1  

g(x)=(4x2−24x+36)+1

g(x)=4x2−24x+37

g(x)=y=4x2−24x+37  

So  4x2−24x+37−y=0⟹x2−6x+37−y4=0⟹(x−3)2−9+37−y4=0⟹(x−3)2=y−14⟹x=3±y−1√2

g−1(x)=3±x−1√2

So the restriction in the room of real numbers is that  x≥1 . In complex world both  g  and  g−1  are defined for each value.

answer: 193

explanation:

200-7 = 193

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation