The answer is: " 26 ft plus 10 inches " .
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or: expressed as units of "feet" (ft.)—only:
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→ " 26 ft. " ; or, write in decimal form: " 26 .583 ft. " ;
or: expressed as units of "inches" (in.)—only:
→ " 322 in " .
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Step-by-step explanation:
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Note: The exact conversion:
" 12 in. = 1 ft. " .
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Note:
→ "in." stands for "inch" [one "inch" or fewer];
or; "inches" [plural form of "inch"]; [more than once "inch".] ;
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"ft" stands for "foot" [one "foot" or fewer]'
or; "feet" [plural form of "foot"]; [more than one "foot".].
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Note: These are measurement of "length" or "distance"; including "width" and "height".
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Given: "19 ft 4 in + 7 ft 6 in. " ;
Find the sum:
[expressed as:
units of "ft." (feet) and units of "in." (inches).].
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Note: "19 ft 4 in" ; is one way of saying "19 ft. Plus 4 in." —referring to a value that is fewer than "20 feet" .
Likewise: "7 ft 6 in" is one way of saying "7 ft plus 6 in." —referring to a value that is fewer than "8 ft." .
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{Note of interest: "6 in. = 0.5 ft. = ft." ;
since: "12 in. = 1 ft." ;
and since: " in. in. ;
→ So: " 7 ft 6 in = 7 ft plus 6 in. = 7 ft + ft = ft ; or write as: " 7.5 ft."}.
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Back to the problem given:
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→ " 19 ft 4 in + 7 ft 6 in " ;
= 19 ft + 4 in + 7 ft + 6 in ;
→ Now; we can combine the "like terms":
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→ 19 ft + 7 ft = 26 ft. ;
→ 4 in + 6 in. = 10 in. ;
Note: " 10 in. " ; is fewer than "12 in" ;
{i.e., is fewer than "1 ft."} ;
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So; we can write our simplified value as:
→ " 26 ft. 10 in."
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The problem does not specify if we are to solve for:
1) The simplified value in "{maximum number of feet ; Plus the [remaining value expressed as inches{" ; which would be:
→ " 26 ft. 10 in." ; [^ see above] ;
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or:
2) The total value expressed as "ft." ["feet"], only; And:
The total value expressed as "in." ["inches"], only ;
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which is fine—so we shall obtain those 2 (two) values—as well!
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We have: " 26 ft plus 10 inches ".
→ To convert this value to units of "ft." ["feet"] only:
Note that "10 inches" = " ft" ;
So: " 26 ft plus 10 inches = 26 ft. " ;
Note: We can reduce the fraction value;
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→ " " ;
→ So; " 26 ft " ;
= " 26 ft. " ;
Or; using calculator, write in decimal form:
26 + (5 ÷ 6) ft. = ? ;
→ " 26 .583 ft. " ;
Source: <<Web2.0 Online Scientific Calculator>>.
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To solve for the value in inches:
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→ " (26 ft) *() " ;
→ The units of: "ft." cancel out to "1" ; [since: " ft / ft = 1".];
→ and we have: " (26 )*(12 in) " = " 322 in. "
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→ Let's check part of our answer:
→ " (322 in.) ÷ 12 ≟ 26.58333333......... ??? " ;
Using calculator: <<Source: Web2.0 Online Scientific Calculator>> :
→ " 322 ÷ 12 = 26.583333333333333..... " ; Yes!
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Hope this is helpful!
Wishing you well in your academic endeavors!
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