100PTS Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region.
y=1/x, y=1/x2,x=6

i tried to use the antiderivative but when i plug 0 in, it turns out ln(6)+1/6-ln(0)-1/0 and i dont know what to do with 1/0 :(

Step-by-step explanation:

We'll integrate with respect to x.

Recall that the area between some and some on the interval is given by:

The function will be the upper bounds of our definite integral. The lower bounds will be the intersection of and . Set the functions equal to each other and solve for x:

Therefore, we'll be integrating the area between and on the interval . In integral notation, this is:

To evaluate this integral, recall that and .

Therefore,

Solving yields:

i got 10.28 but that rounds up to 10.3