The figure below shows CAD and angle bisector AE. Line segments ED and BC have been drawn to form AAED and AABC.
A
P
Points C and D are equidistant from point A. Complete the following table to prove that
ΔAECA ΔΑΕD.
Statement
Reason
1. Points Cand D are equidistant from point A Given
AE is the
2. AD
3.Z CAE
4 AE
5.AEADS -

kekdkdkccc

so

step-by-step explanation:

kekdkckcldlx

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

idk what the heck he answer is, i’m just putting this here so i finish my account

kaahe btau