Can someone please help me as soon as possible, I need the answer.

4:5

Step-by-step explanation:

because I already answer it when I am in grade6 and my answer is 4:5 and it's correct but I think it helps

Solution:

We know that:

Let's find the perimeter of both the triangles.

Now, let's put them together into ratio form from ΔBDF to ΔCEG.

Let's simplify the ratio.

Cancel out the 45 from both sides as a:b = a/b.

Hence, the ratio from ΔBDF to ΔCEG is 4:5

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐