Mathematics, 22.01.2022 14:30 keely6940
S is the circumcircle of △ABC. Bisectors of ∠A, ∠B, ∠C meet S
at P, Q, R respectively. I is the incenter of △ABC.
1: Prove that I is orthocenter of △P QR.
2: Given m∠P = 70, m∠Q = 54, find m∠A.
3: Given BI = 6, BR = 8, BP = 10, find P R.
4: Given m∠P IR = 110, find m∠ABC.
Answers: 1
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S is the circumcircle of △ABC. Bisectors of ∠A, ∠B, ∠C meet S
at P, Q, R respectively. I is the in...
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