7. The product of two consecutive odd numbers is 399. Find the sum of the squares of the numbers.

solution set

1:19 and 21

solution set

2:-21 and -19

802

Step-by-step explanation:

Let x stand for one of the numbers.

"consecutive" means in a row. So consecutive odd numbers are like 1, 3, 5, 7, 9, 11, 13... SO you could just guess and check. Like, 20×20 is 400 so 19×21 is a good guess and it works, so ??? you could just run with it from here. Bt,

the math is

x is a number (hopefully, ODD)

x + 2 would be the next odd number.

x(x+2) = 399

x^2 + 2x = 399

x^2 + 2x - 399 = 0

(x - 19)(x + 21) = 0

x-19=0 and x+21=0

x=19 and x= -21

We'll use the 19. So the next odd number is 21. But don't stop there. Re-read the question...they mysteriously want the sum (adding) of the squares (2nd power)

19^2 + 21^2

= 361 + 441

= 802

it would open into a square depending on the type of envelope i’m not sure about the second part

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: