I am confused about ii) help please

Step-by-step explanation:

i)=

m=2/3

x=-3

y = 5

now

y=mx+c

or, 5 = 2/3× -3 + c

or, 5 = -2+c

c =7

now,

y= mx + c

or, y = 2/3×x+7

or, y = 2x/3+7

or, 3y = 2x+21

so, 3y-2x=21

equation would be 3y-2x=21.

now

ii)=

if slope of 3y-2x=21 and 2x-3y = 0 are same, they are parallel.

2x-3y = 0

2x = 3y

lets suppose x is 9

now

2x=3y

2×9 = 3y

or, 18 = 3y

so, y = 6

one coordinate would be (9,6) now

lets again suppose x is 3

2x=3y

2×3 = 3y

or, 6 = 3y

so, y = 2

another coordinate is (3,2)

now lets find slope

x1=9,y1=6

x2=3,y2=2

slope = (y2-y1)/(x2-x1)

= (2-6)/(3-9)

= -4/-6

= 2/3

Since, slope of 3y-2x=21 and 2x-3y has same slope 2/3, they are parallel.

you have 6 cupcakes