Help would be much appreciated

Figure is not accurate but i drew AE such that it is equal to BD and ED is equal to AB and AE is perpendicular to CD. And also ABDE is a rectangle.

Step-by-step explanation:

CD:AB

or, let CD be x

now

CD:AB= 1.5:1

or, x : 1.7 = 1.5 : 1

or, x/1.7 = 1.5/1

or, x = 2.6 m

CD = 2.6 m

ED=AB=1.7 m

now

CD = CE + ED

or, 2.6m =CE + 1.7m

or, CE = 2.6 m - 1.7 m

so, CE = 0.9 m

now

triangle CEA is a right angled triangle,

In triangle CEA, taking 52 as reference angle

tan52° = p/b

or,tan52° = CE/AE

or, tan52° = 0.9/AE

or, AE = 0.9/tan52°

so, AE = 0.7

now

AE = BD (given in the figure i uploaded)

so, BD = 0.7 m

goog may have it for you