A man is four times as old as his son. After 20 years, he will be twice as old as his son. Their present ages are and

17&13 father will 17 and son will be 13

10 and 40

Step-by-step explanation:

let the son's age be x then the father's age is 4x

After 20 years

son is x + 20 and father is 4x + 20

The father is now twice as old as his son , that is

4x + 20 = 2(x + 20) ← distribute parenthesis

4x + 20 = 2x + 40 ( subtract 2x from both sides )

2x + 20 = 40 ( subtract 20 from both sides )

2x = 20 ( divide both sides by 2 )

x = 10 and 4x = 4 × 10 = 40

Thir present ages are , son is 10 and father is 40

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

can someone answer this question plz

step-by-step explanation: