(x + a)(x + 3)(2x+1) = bx^3 + cx^2 + dx -1(x + a)(x + 3)(2x+1) = bx^3 + cx^2 + dx -10. find values for a b c and d

a=-5,b=3,c=-8 but I don't know what d is

Step-by-step explanation:

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

95.03 is the answer. hope this !