Solve for x ~

thankyou ~

let's solve ~

Therefore, the required values of x are ~

x = 3,4

Step-by-step explanation:

Above is formula for factoring of two brackets for a = 1 from ax^2 + bx + c.

First, find the factors of 12:

If we multiply the factors together, we get same ab-value which is 12. Next, we find the middle term. A middle term can’t be found by adding factors together.

Our middle term is -7x and the only factors that satisfy -7x would be 3 and r using (x-a)(x-b) standard.

Hence, our a is 3 and b is 4. Substitute in:

Set (x-3)(x-4) = 0 then we obtain:

x-3 = 0 or x-4 = 0 —> solve like linear by transporting the constant and change the sign.

Hence, “x = 3 or x = 4”

You can also write x = 3,4 instead or x = 4,3.

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)