Find the equation of the line passing through f(1)= -2 and perpendicular to 3x-2y-4=0. Give answer in function notation

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Step-by-step explanation:

Rewrite the slope of the given line by rewriting to equation of that line into the slope-intercept form :

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Thus, the slope of the given line would be .

Let denote the slope of the line in question. Two lines in a plane are perpendicular to one another if and only if the product of their slopes is . Thus, since these two lines are perpendicular to one another.

Since , the slope of the line in question would be:

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Let denote the -intercept of the line in question (the value of this needs to be found.) The slope-intercept equation of the line in question would be:
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In other words, for a point on this line, if the input (-coordinate) is , the output (-coordinate) would be . This relation is equivalent to the function:

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The question stated that . In other words, should evaluate to when the input variable is replaced with . Thus:

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Solve for :

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Therefore, the function that represents this line would be:

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Here's another example on how to find the equation of a line perpendicular to a given line:

side side side

side angle angle

angle side angle

side angle side

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180