BRAINLIEST +20 pts Given trapezoid ABCD with vertices A(1,2) B(7,5) C(5,7) and D(3,6)

The length of the midsegment in simplest radical form is

The equation of the line containing the midsegment is

Distance formula: (x1,y1), (x2,y2)

d = √[(x2-x1)2+(y2-y1)2]

d = √[(5-2)2+(4-1)2]

d = √(32+32)

d = √18

d = 3√2

double this distance: The length is 6√2

it's of first one

Step-by-step explanation:

its of second one

The formula for midpoint = (x1 + x2)/2, (y1 + y2)/2. Substituting in the two x coordinates and two y coordinates from the endpoints, we get (–1 + 3)/2

i think is g(1)=-1.

hope that i can

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