Find the equation of the line parallel to y = 3x + 2 that passes through the point (2, 10).

y = 3x + 4

Step-by-step explanation:

A parallel line has the same slope as the reference line.

y = mx + b  (m is the slope and b is the y-intercept)

The reference line, y = 3x + 2, has a slope of 3.

We need another line of the form y = 3x + b,  So all we need is a new b.  Any value we choose for b will result in a straight line.  But our line needs to go through point (2,10), so we need a specific value for b that will move the line to the appropriate position.

We can find b by entering the point and solving for b:

y = 3x + b      (2,10)

10 = 3*(2) + b

b = 4

The equation becomes y = 3x + 4

the awnser is visionary

6 equilateral triangles