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5 What is the equation of the line that passes
through the point (3,-7) and has a slope of -4/3

Given that a line passes through the point (3,−7) and has a slope of −43. − 4 3 . Hence, the equation of the given line is 4x+3y+9=0.

y = -4x/3 -3

Step-by-step explanation:

y -  y1 = m( x - x1 )

y - -7 = -4/3 ( x - 3 )

y + 7 = -4x/3 + 4

y = -4x/3 -3

y = -4x/3 -3 is the equation of the line

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3