Mathematics, 27.01.2022 14:00 jamilamiller200

HELP I NEED HELP WE BARELY STARTED LEARNING THIS

HELP I NEED HELPPPPPPP WE BARELY STARTED LEARNING THIS

Answers: 3

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Answer from: millie54

The Answer to the first one is x = 2. Here's an explanation so you can try and solve the others.

Step-by-step explanation:

First, y = x + 2. Meaning we can substitute the y in 2y. So, we get:

4x + 2(x + 2) = 164x + 2x + 4 = 16 Use distributive property 6x + 4 = 16 Add like terms6x + 4 - 4 = 16 - 4 Subtract 4 on both sides of the equation.6x = 12 Divide both sides by 6 to isolate xx = 2

For the next equation:

Since both equations equal y, you must put them side by side.

3x - 4 = -2x + 63x - 4 + 4 = -2x + 6 - 4 Subtract 4 on both sides3x = -2x + 2 Add 2x on both sides 3x + 2x = 2 Combine like terms5x = 2x = 0.4

With the 3rd one just substitute x in 3x with the equation it provides you with (y + 1) and solve (like in the first one).

Same thing with the last one (solve like the second one, side by side), since both equations equal y.

Hope this helps!!

Answer from: Quest

answer:

total cost for tiles and paints is $924.

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

$\text{area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)$

$\text{area of walls and ceiling}=1200+90+120$

$\text{area of walls and ceiling}=1410$

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

$\text{ the total painting cost}=10*(\frac{1410}{25})$

$\text{ the total painting cost}=10*56.4=564$

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

$\text{area of floor} = 40*3\text{ square meters}$

$\text{area of floor} =120\text{ square meters}$

given: 1m squared floor tiles costs $3. so,

$\text{total cost for tiles} = 3*120 = 360$

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

$\text{combined total cost}= 564+360 = 924$

therefore, the combined total cost of tiles and paint is $924.

Answer from: Quest

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)

Which graph shows a system with no solution?

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