Write an equation of the line with slope 2/3 that goes through the point (-2,5) (if possible can you also write an equation of a line that passes through (-1,2) and is parallel to a line with x-intercept (0,1), please and thank you!)

a

step-by-step explanation:

250

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet