In the diagram, AB passes through the center C of the circle and DC is paralell to AB. Name two triangles that are congruent. A circle is drawn with triangle ADB inside and a center point C is given for the circle, which runs through the line AB, which is the base of the triangle. The triangle is divide in half by line CD which is perpendicular to line AB. The divided line makes two triangles: Triangle DCA and Triangle ACD.

A.
DCA ≅ ACD

B.
∆DAC ≅ ∆DBC

C.
DCA≅CBD

D.
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intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

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b.

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