Places a and b are 80km apart. car x starts at a and car y starts at b. if the cars travel in the same direction(car x moving towards b) with different uniform speeds, they meet each other after 4 hours from the start of their journey. if they travel towards each other, they meet in 2 hours. find the speed of car x Please help :)

hope it helps

Step-by-step explanation:

Let the speed of car starting from A=x km/hr and speed of car starting from B=y km/hr.The relative speed of A with respect to B when moving in the same direction =x−y km/hr.The relative speed of A with respect to B when moving in opposite direction =x+y km/hr.Distance between A and B=80 km.We know, Time=SpeedDistanceFrom the above information, we have,x−y80=8andx+y80=1+6020=34or,x−y80=8⇒10=x−y⇒x−y=10(i)Also,x+y80=34⇒240=4(x+y)⇒x=60−y(ii)Substituting (ii) in (i), we get,x−y=10⇒60−y−y=10⇒60−2y=10⇒2y=50⇒y=25Substituting y=25 in equation (ii), we get,x=60−y⇒x=60−25⇒x=35Thus, the speed of car starting from A=x=35 km/hr and speed of car starting from B=y=25 km/hr.

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!