Given a line with slope of -1 and y-intercept of 8, which of the ordered pairs given below would NOT be on the line? (2, 10)

(-1, 9)

(0, 8)

(3, 5)

(2,10) and (-1,9) would NOT be on the line

Step-by-step explanation:

question is describing this linear equation:

y = -x + 8

(2,10)  Does 10 = -2 + 8?   NO

(-1,9)  Does 9 = -1 + 8?      NO

(0,8)  Does 8 = 0 + 8?     YES

(3,5)  Does 5 = -3 + 8?     YES

the point (2,10) would not be on the line because it's in the positive x direction.

Step-by-step explanation:

y = -x + 8

10 = -2 + 8

10 + 2 = 8

2 = -10 + 8

2 = -2

(hope this helps you!)

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

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step-by-step explanation: