Explain how to write an equation for the line that contains the point (2, -3) and is parallel to the graph of x + 2y = 2

The equation of the line which is parallel to the given line and passing through the given point is x + 2y + 2 = 0

It is an endless 1-dimension figure that has no width.

Given

Line x + 2y = 2

Point (2, -3)

Equation of parallel line is given by ax + by + c = 0

But the line is parallel to the given line x + 2y -2 = 0 so the coefficients of x and y will be the same.

a = 1

b = 2

Then line becomes x + 2y + c = 0

The line is passing through the point (2, -3)

Then the equation of the line which is parallel to the given line and passing through the given point is x + 2y + 2 = 0

Thus, the equation of the line which is parallel to the given line and passing through the given point is x + 2y + 2 = 0

More about the straight-line link is given below.

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier