DUDE PLS HELP IM BEGGING

x = 50°

Step-by-step explanation:

since angle BCD and angle CBD lie on the ends of the same length of lines i.e. BD and CD. angle BCD = angle CBD = 60°.

Angle ADC = 180° - (angle CAD + angle ACD)

= 180° - ( 10° + 60° )

= 180° - 70°

= 110°

angle BDC = 180° - (angle BCD + angle CBD)

= 180° - (60° + 60°)

= 180° - 120°

= 60°

x = angle ADC - angle BDC

= 110° - 60°

= 50°

x=50

Step-by-step explanation:

Since Angle BCD = 60 and Angle BAD = 10, Angle CDA must equal 60+10+Angle CDA=180 70+Angle CDA=180 Angle CDA=110

Since Angle BCD is 60 and Angle CDB is 110-x, Angle DBC must equal 110-x+60+Angle DBC=180 Angle DBC+170-x=180 Angle DBC=10+x

Since Triangle BCD is an isoceles triangle, 60=10+x, x=50

its definatley   this on your answer choice?

what is the original number? you forgot to add it.