Leah has two savings accounts with balances totaling $8,000. She withdrew 15% from one and 40% from the other. If she has $6,350 remaining in the accounts, how much money did she
withdraw from the account with the larger balance?

930 Hope this Helps :D

Step-by-step explanation:

For the given problem:

Let the balances of the saving accounts be (x) and (y)

Leah has two savings accounts with balances totaling $8,000

so,

x+y=8000 (1)

She withdrew 15% from one and 40% from the other. If she has $6,350 remaining in the accounts

So, The remaining from the accounts will be (1 - 15%) and ( 1 - 40%)

that will give the decimals: 0.85 and 0.6

so, we can write the following equation:

0.85x+0.6y=6350 (2)

Now, solve the equations (1) and (2) to find (x) and (y)

From equation (1)

y=8000-x (3)

Substitute with (y) from equation (3) into equation (2)

0.85x+0.6*(8000)-x =6350

Now solve the equation

0.85x+0.6*8000-0.6x=6350

0.85x-0.6+4800+6350

0.25x=6350-4800

0.25x=1550

x=6200

Substitute with (x) into equation (3) to find (y)

y=8000-6200=1800

So, the larger account = x = 6200

and the smaller account = y = 1800



Now, we will answer the question, how much money did she withdraw from the account with the larger balance?

so, the answer will be: 15% of x = 0.15 * 6200 = 930



So, the answer will be $930

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.