2. What extraneous solution arises when the equation x + 3 = 2x is solved for
x by first squaring both sides of the equation?
Enter your answer in the box.

x = -3/4

Step-by-step explanation:

I assume the question is

√(x + 3) = 2x

Square both sides.

x + 3 = 4x²

4x² - x - 3 = 0

(4x + 3)(x - 1) = 0

4x + 3 = 0 or x - 1 = 0

x = -3/4 or x = 1

Check solution x = -3/4 in the original equation.

√(x + 3) = 2x

√(-3/4 + 3) = 2(-3/4)

This solution cannot work since the right side is negative, and a square root cannot equal a negative number.

Check solution x = 1 in the original equation.

√(x + 3) = 2x

√(1 + 3) = 2(1)

√4 = 2

2 = 2

Solution x = 1 works.

x = -3/4

the answer is b i just did that

step-by-step explanation: