I NEED THESE ANSWERS ASAP QUESTION 1) Find the zeros of the expression

(h-4)(h+5)(h-3)

a) -4,5,-3

b) 4,-5,3

c) -4,-5,3

d) -4,-5,-3

QUESTION 2) Factor the expression to find the zeros

k^2 - 5k +4

a) -5,4

b) 5,-4

c) 1,4

d) -1,-4

QUESTION 3) Match the quadratic equations with the correct zeros.

1) m^2-121 a. -3/2 , 1

2) 4x^2+2x-6 b. -1/3 , 2/3

3) 9x^2-3x-2 c. 11, -11

QUESTION 4) Factor the following quadratic function to find the zeros.

f(x)=x^2-15x-16

a. x=16 x= -1

b. x=8 x=-2

c. x= -16 x=1

d. x=5 x=3

QUESTION 5) The factored form of a quadratic expression is (x+a) (x+b), where a and b represent positive constants. Which statement describes how to determine one zero of the related quadratic function?

a) Find the sum of the two constants.

b) Find the opposite of one of the constants.

c) Find the difference between the two constants.

d) Find the ratio of the smaller to the larger constant.

can i get the link to the assignment?

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

solve systems of equations by graphing. a system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. the solution of such a system is the ordered pair that is a solution to both equations. to solve a system of linear equations graphically we graph both equations in the same coordinate system