At a large university, 20% of students are enrolled in the nursing program. The dean of students selects a random sample of 20 students and records n = the number of students enrolled in the nursing program. The dean decides to simulate this random process by using a random number table. He assigns the digits to the outcomes. 1 = student enrolled in nursing program

2–5 = student not enrolled in nursing program

Skip 6–9 and 0

How can the dean use a random number table to simulate one trial of this situation?

He can select a row of the random number table and read 20 single digits between 1 and 5. He will record the mean of the 20 digits.
He can select a row of the random number table and read 20 single digits between 1 and 5. He will record the number of digits that are a 1.
He can select a row of the random number table and read 100 single digits between 1 and 5. He will record the number of digits that are a 1.
He can select a row of the random number table and read 100 single digits between 1 and 5. He will record the percentage of the digits that are a 1.

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

vertical=18cm horizontal=18cm hypotenuse=25.5

step-by-step explanation:

whew you’re speaking a different language