Hattie had $6600 to invest and wants to earn 4% interest per year. She will put some of the money into an account that earns 2.7% per year and the rest into an account that earns 4.9% per year. How much money
should she put into each account?

The amount of money that should be invested at the rate of 12% is $900 and the amount of money that should be invested at the rate of 10% is $2,100

Step-by-step explanation:

Let

x > the amount of money that should be invested at the rate of 12%

3,000-x > the amount money that should be invested at the rate of 10%

we know that

The sum of the interest on each of the accounts must be equal to the total interest.

Solve for x

therefore

The amount of money that should be invested at the rate of 12% is $900 and the amount of money that should be invested at the rate of 10% is $2,100

Hope this helps you :D

phosphate, calcium ion, chloride ion, neon atom

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.