Mrs. Watson tell you that a right triangle has a leg of 10.5 inches and another leg half of the first leg. She asks you to find the hypotenuse of the triangle. What is your answer? show work

11.74 inches

Step-by-step explanation:

10.5 = first leg

second leg = 1/2 of 10.5 = 5.25

the use pythagoras theorem to solve

c^2=a^2+b^2

your answer should be 11.74 inches.

hope this helped :)

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

translate k to n and reflect across the line containing jk.