Alalalalalalalalalalalalalallalalal alalalalalalalalalalalalal

-4

Step-by-step explanation:

There are many methods to solve this system of equations.

I will use the elimination method.

First step:

Multiply the first equation by -2

2(2x-3y) = -14(-2)

-4x + 6y = 28

Multiply the second equation by 3 so you can eliminate the y term

3(3x-2y) = -6(3)

9x-6y = -18

Second step: Add the equations vertically(Basically adding like terms)

-4x+6y = 28

     +

9x - 6y = -18

5x = 10

Third step: Solve for x

x = 2

Substitute the x-value into any of the original equation to get the y value

3(x) - 2y = -6

3(2) - 2y = -6

6 - 2y = -6 (Since we are solving for y, it will be isolated and we will move 6 to the other side)

-2y = -6 - 6(Moving 6 to the other side makes it negative)

Solve for y by dividing by -2

y = 6

So (x, y) = (2, 6)

Since the question is asking to subtract x and y

2-6 = -4

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.