Mathematics, 07.02.2022 05:20 ashgold324
(m^2 - 16n^2) / [(3m+12n)/mn]
Answer appears to be correct: mn(m - 4n)/3 for
I can't figure out the limitation -- tried m≠0, n≠0, m≠-4n and shows as incorrect. Also tried m≠0, n≠0 and just m≠4n. Shows as incorrect. Help would be very much appreciated!
Answers: 2
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(m^2 - 16n^2) / [(3m+12n)/mn]
Answer appears to be correct: mn(m - 4n)/3 for
I can't...
I can't...
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