I'm Pretty Desperate 100 POINTS AND WILL BE MARKED BRAINLIEST
ONLY if your answer shows steps and is logical
If it is obviously incorrect, it will be reported

a. Find the domain and range of f(x)=2log_3(x^2-4x-5)

b. find the domain and range of the function f(x)=5/(2+3^x)

c. If 8^x=27, then what is 4^(2x-3)

for c

8x

4

−2x

3

−27x

2

+6x+9=0

Let the roots be a,−a,b,c

S

1

=a−a+b+c=−

8

−2

=

4

1

b+c=

4

1

(i)

S

3

=−a

2

b−abc+abc−a

2

c=−

8

6

⇒a

2

(b+c)=

4

3

(ii)

dividing (i) by (ii)

⇒b+c=

4

1

(iii)

S

4

=−a

2

bc=

8

9

⇒bc=−

8

3

(iv)

substituting b from (iii) in (i)

b(

4

1

−b)=−

8

3

4

b−4b

2

=−

8

3

2b−8b

2

=3

8b

2

−2b−3=0

8b

2

+4b−6b−3=0

4b(2b+1)−3(2b+1)=0

(4b−3)(2b+1)=0

⇒b=

4

3

,−

2

1

substituing b in (iv)

⇒c=−

2

1

,

4

3

S

2

=a(−a)+(−a)(b)+bc+ca=

8

−27

⇒−a

2

−ab+bc+ac=

8

−27

The value of s

4

is not satisfied for b=−

2

1

So the roots of the equation are

3

,−

3

,

4

3

,−

2

1

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation: