A, B and C form the vertices of a triangle BC = 6.9cm and ZCBA 137,
Given that the area of the triangle is 12.6cm, calculate the perimeter of the triangle rounded
to 1 DP

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.

Distance is always positive