Jim has received scores of 75
and
81
on his first two 100 point tests.
What score must he get on his third 100 point test to keep an average of
84
or greater?

t ≥ 96   test score must be 96 or greater

Step-by-step explanation:

Let t - score on his third test

   (75 + 81 + t) ÷ 3 ≥ 84

⇒ (75 + 81 + t) ≥ 84 x 3

⇒ (75 + 81 + t) ≥ 252

⇒ 156 + t ≥ 252

⇒ t ≥ 252 - 156 ≥ 96

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

pls mark as brainliest