Find the 14th term of the arithmetic sequence whose common difference is d= -9 and whose first term is a, = 10.

The 14th term of arithmetic sequence is -107.

Step-by-step explanation:

Here's the required formula to find the arithmetic sequence :

Substituting all the given values in the formula to find the 14th term of arithmetic sequence :

Hence, the 14th term of arithmetic sequence is -107.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

99

step-by-step explanation: