The vertices of quadrilateral ABCD are given. Draw ABCD in a coordinate plane and show that it is a parallelogram. A(-2, 3), B(-5, 7), C(3, 6), D(6, 2)

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50