Find a degree 3 polynomial with real coefficients having zeros 3 and 4i and a lead coefficient of 1. Write
P in expanded form.

Since 4 - 2i is a zero, 4 + 2i is also a zero.

Step-by-step explanation:

x = 2, x = 4 - 2i, x = 4 + 2i

x - 2 = 0, x - 4 + 2i = 0, x - 4 - 2i = 0

P(x) = (x - 2)(x - 4 + 2i)(x - 4 - 2i)

P(x) = (x - 2)(x2 - 8x + 20)

P(x) = x3- 10x2 + 36x - 40

126 maybe. sorry

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5