A plant has an initial height of 2 inches and grows at a constant rate of 2 inches each month. A second plant that also grows at a constant rate has an initial height of 1 inch and is 29 inches tall after 1 year. After how many months are the plants the same height?

4.8 monthsStep-by-step explanation:First, let's write down the information that we are given.Plant A: Initial Height: 3 in.Constant Rate of Growth (CRG): 2in/month (2 inches per month)Plant B:Initial Height: 1 in.CRG: 29in/year (29 inches per year)We can see that Plant B grows 29 inches per year, so lets convert Plant B's 'CGR' to months.Plant B - Divide by 12 (12 months in a year)29/12 in/yearNow, Lets put these into equations:Plant A: y = 2x + 3Plant B: y = 29/12 x + 1Now, set these two equations together and solve for x.2x + 3 = 29/12 x + 12 = 5/12 x4.8So, after 4.8 months, the plants will be the same height.

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intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

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