Y=4x-1 y=2x-5
It uses substitution and I know the answer, but I struggle with the process on how to get the answer.

(-2, -9) or x=-2, y=-9

Step-by-step explanation:

First, isolate x in one of the equations.

y = 4x-1

y+1 = 4x

(y+1)/4 = x

Next, substitute in (y+1)/4 for x in the second equation.

y = 2x-5

y = 2[(y+1)/4]-5

y = (y+1)/2 - 5              

At this point, break up your fraction so you can isolate y.

y = (y+1)/2 - 5

y = y/2 + 1/2 -5

y - y/2 = 1/2 - 5

y/2 = -9/2

y=-9

Finally, substitute -9 for y in either equation to find x.

y = 4x-1

-9 = 4x-1

-8 = 4x

x=-2

Your answer is (-2, -9) or x=-2, y=-9

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation: