Hi i have no idea does anyone have an idea ? please

y = 2(x+5)²- 60

Step-by-step explanation:

f(x) = ax² +bx +c,  is the standard form

f(x) = a(x - h)² +k , is the vertex form where the (h, k) is the vertex

y = 2x²+20x -10 ,

factor 2 from the two terms

y = 2(x² +10x) -10,

what perfect square has x² +10x? ... x²+10x +25 = (x+5)²

y = 2(x²+10x+25 )- 50 -10,

add 25 in parenthesis to get a perfect square yet subtract 2*25 = 50 so the equation will stay the same

y = 2(x+5)²- 60,

the equation has the vertex at (-5, -60)

answer: i'm great at algebra

~coco

step-by-step explanation:

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1