A new car is purchased for $23,700 the value of the car depreciates at 13. 5% per year what will the value the car be to the nearest cent after 10 years

Compound interest

$5557.88

Step-by-step explanation:

Everything starts at 100% and since it depreciates you subtract 13.5 from 100 =86.5% now we want percentage as a decimal so we divide by 100=0.865 our multiplier

Now you have the original amount that you purchased for times by the multiplier to the power of number of years=10

23700 times 0.865 power of 10

=5557.88

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form