On a coordinate plane, an exponential function approached y = 0 in quadrant 2 and increases into quadrant 1. It crosses the x-axis at (0, 2). What is the initial value of the exponential function shown on the graph?

0
1
2
4

the png will show the answer to the question. I hope it helps,, if it dosent then I’ll try answering again

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)