What are the solutions to the following equation? (x−4)2=64
Question 3 options:

-68 and -60

60 and 68

-4 and 12

-12 and 4

-4 and 12

Step-by-step explanation:

(x-4)² is the same as (x-4)(x-4)

now we have

(x-4)(x-4) = 64

expand (x-4)(x-4)

x²-4x-4x+16 which is simplified to x²-8x+16

equate to 64

x²-8x+16 = 64

subtract 64 on both sides

x²-8x+16-64 = 0

x²-8x-48 = 0

to find x

what two numbers multiply to give -48 and add to give -8? That is -12 and 4 which we can write in brackets

(x-12)(x+4) = 0

equate each bracket to 0 to find x

x-12 = 0 and x+4 = 0

x = 12 and x = -4

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation:

step-by-step explanation:

20-2= what