Triangle ABC has perimeter 22cm AB = 8cm
BC = 5cm

By calculation, deduce whether triangle ABC is a right-angled triangle

Step-by-step explanation:

To calculate this we use Pythagoras' theorem: a^2+b^2=c^2

in this case a=8cm, b=5cm and c=22

so we do 8^2+5^2=89

the square root of 89 is 9.4 (1 d.p)

8+5+9.4=22.4 so rounded (22), this triangle is a right-angled triangle since Pythagoras theorem has proved ABC is a right-angled triangle

i can

step-by-step explanation:

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option